Question 1
For the given data set, find the a. mean b. median c. mode (or state that there is no mode) d. midrange.
Ages of teachers in the mathematics department of a certain high school:
25, 55, 38, 60, 25, 55, 25, 47, 47, 41
◦ a. 41.8
b. 44
c. 47
d. 42.5
◦ a. 31.3
b. 44
c. 25
d. 42.5
◦ a. 26.6
b. 44
c. 25
d. 42.5
◦ a. 41.8
b. 44
c. 25
d. 42.5
Question 2
For the given data set, find the a. mean b. median c. mode (or state that there is no mode) d. midrange.
A company advertised that, on the average, 96% of their customers reported "very high satisfaction" with their services. The actual percentages reported in 15 samples were the following:
96, 96, 92, 35, 74, 96, 92, 74, 96, 96, 35, 92, 92, 96, 35
a. Find the mean, median, mode and midrange. b. Which measure of central tendency was given in the advertisement? c. Which measure of central tendency is the best indicator of the "average" in this situation?
◦ a. mean = 79.8, median = 92, mode = 96, midrange = 65.5
b. median
c. mean
◦ a. mean = 79.8, median = 92, mode = 96, midrange = 65.5
b. mode
c. mode
◦ a. mean = 79.8, median = 92, mode = 96, midrange = 65.5
b. mode
c. median
◦ a. mean = 79.8, median = 92, mode = 96, midrange = 65.5
b. mode
c. mean
Before the stick is broken, it must first be bent (the transition state).
4.1 Age changes in total IQ based on cross-sectional data (lower line) and longitudinal data ...
Midsagittal or median plane along with a sagittal view of the head.
How to use L’Hospital’s Rule to find the limit of a function (Part 1)
How to find the components of a vector found in the first quadrant
Histograms - Analysis and Data