Author Question: A retired statistician was interested in determining the average cost of a $200,000.00 term life ... (Read 151 times)

@Brianna17 · **on:** Feb 14, 2020

A retired statistician was interested in determining the average cost of a $200,000.00 term life insurance policy for a 60-year-old male non-smoker. He randomly sampled 65 subjects (60-year-old male non-smokers) and constructed the following 95 percent confidence interval for the mean cost of the term life insurance: ($850.00, $1050.00). State the appropriate interpretation for this confidence interval. Note that all answers begin with "We are 95 percent confidence that…"
◦ The average term life insurance cost for sampled 65 subjects falls between $850.00 and $1050.00
◦ The term life insurance cost of the retired statistician's insurance policy falls between $850.00 and $1050.00
◦ The average term life insurance costs for all 60-year-old male non-smokers falls between $850.00 and $1050.00
◦ The term life insurance cost for all 60-year-old male non-smokers' insurance policies falls between $850.00 and $1050.00

zhanghao · **Reply #1 on:** Feb 14, 2020

A FREE account is required to view all solutions!

Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.

Answer Preview

Only 25% of students answer this correctly