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Author Question: Calculate the enthalpy of combustion per mole for C6H12O6. Assume that the combustion products are ... (Read 657 times)

bio_gurl

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on: Feb 15, 2020

Question 1

Heat of formation for CO is -110.5 KJ/mol and the heat of formation for MgO is -602 KJ/mol.  Which of the following statements is true?
◦ The bond in CO is stronger than the bond in MgO.
◦ The bond in MgO is stronger than the bond in CO.
◦ Impossible to determine to given data.
◦ The bonds in MgO and CO are equally strong.

Question 2

Calculate the enthalpy of combustion per mole for C6H12O6. Assume that the combustion products are CO2(g) and H2O(l).



◦ -1939 kJ/mol
◦ 580.7 kJ/mol
◦ -5336 kJ/mol
◦ -2816 kJ/mol
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by bio_gurl on Feb 15, 2020

apple

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bio_gurl

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Reply 2 on: Feb 15, 2020
Wow, this really help

Hdosisshsbshs

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Reply 3 on: Yesterday
:D TYSM

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