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Author Question: A gas absorbs 0.0 J of heat and then performs 13.1 J of work. The change in internal energy of the gas is (Read 139 times)

haleyc112

  • Hero Member
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  • Posts: 600
on: Feb 15, 2020

Question 1

At constant pressure for which of the reactions shown below should ΔH° be greater than ΔE° ?

I.2 SO2(g) + O2(g) → 2 SO3(g)
II.C9H20(g) + 14 O2(g) → 9 CO2(g) + 10 H2O(l)
III.H2(g) + F2(g) → 2 HF(g)
IV.N2O4(g) → 2 NO2(g)

◦ I
◦ IV
◦ III
◦ II and IV

Question 2

A gas absorbs 0.0 J of heat and then performs 13.1 J of work. The change in internal energy of the gas is
◦ 26.2 J
◦ -26.2 J
◦ 13.1 J
◦ -13.1 J
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by haleyc112 on Feb 15, 2020

kaylee05

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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haleyc112

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Reply 2 on: Feb 15, 2020
Thanks for the timely response, appreciate it

kalskdjl1212

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Reply 3 on: Yesterday
:D TYSM

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