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Author Question: Calculate the pH of a 0.020 M carbonic acid solution, H2CO3(aq), that has the stepwise dissociation ... (Read 208 times)

Pineappleeh

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Question 1

What is the second stepwise equilibrium constant expression for phosphoric acid H3PO4?
Ka2 = ([H3O+]2[HPO42-])/([H3PO4])
Ka2 = ([H3O+][HPO42-])/([H2PO4-])
Ka2 = ([H3O+][H2PO4-])/([H3PO4])
Ka2 = ([H3O+]3[PO43-])/([H3PO4])

Question 2

Calculate the pH of a 0.020 M carbonic acid solution, H2CO3(aq), that has the stepwise dissociation constants Ka1 = 4.3 × 10-7 and Ka2 = 5.6 × 10-11.
◦ 6.37
◦ 1.70
◦ 10.25
◦ 4.03


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Marked as best answer by Pineappleeh on Feb 15, 2020

hugthug12

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Pineappleeh

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Reply 2 on: Feb 15, 2020
Great answer, keep it coming :)


meow1234

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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