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Author Question: What is the approximate value of the equilibrium constant, Kn, for the neutralization of acetic acid ... (Read 46 times)

anjilletteb

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Question 1

What is the equation relating the equilibrium constant Kn for the neutralization of a weak acid with a weak base to the Ka of the acid, the Kb of the base and Kw?
Kn =
Kn = 1/KaKbKw
Kn =
Kn =

Question 2

What is the approximate value of the equilibrium constant, Kn, for the neutralization of acetic acid with potassium hydroxide, shown in the equation below? The Ka for acetic acid is 1.8 × 10-5.

CH3CO2H(aq) + KOH(aq) ⇌ H2O(l) + NaCH3CO2(aq)


◦ 1.8 × 10-8
◦ 1.8 × 109
◦ 1.8 × 10-19
◦ 5.6 × 10-10


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Marked as best answer by anjilletteb on Feb 15, 2020

amcvicar

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anjilletteb

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Reply 2 on: Feb 15, 2020
Great answer, keep it coming :)


peter

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Reply 3 on: Yesterday
:D TYSM

 

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