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Author Question: What is the approximate value of the equilibrium constant, Kn, for the neutralization of acetic acid ... (Read 69 times)

anjilletteb

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on: Feb 15, 2020

Question 1

What is the equation relating the equilibrium constant Kn for the neutralization of a weak acid with a weak base to the Ka of the acid, the Kb of the base and Kw?
◦ Kn =
◦ Kn = 1/KaKbKw
◦ Kn =
◦ Kn =

Question 2

What is the approximate value of the equilibrium constant, Kn, for the neutralization of acetic acid with potassium hydroxide, shown in the equation below? The Ka for acetic acid is 1.8 × 10-5.

CH3CO2H(aq) + KOH(aq) ⇌ H2O(l) + NaCH3CO2(aq)


◦ 1.8 × 10-8
◦ 1.8 × 109
◦ 1.8 × 10-19
◦ 5.6 × 10-10
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by anjilletteb on Feb 15, 2020

amcvicar

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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anjilletteb

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Reply 2 on: Feb 15, 2020
Wow, this really help

connor417

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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