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Author Question: According to the third law of thermodynamics, (Read 38 times)

rosent76

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on: Feb 15, 2020

Question 1

What is the sign of ΔS for each of the following processes?

I.The separation of gaseous molecules of UF6, into 238UF6 and 235UF6
​at constant temperature and pressure.
II.The dissolving of I2(s) in CCl4(l).

◦ ΔS is positive for I and negative for II.
◦ ΔS is negative for I and negative for II.
◦ ΔS is negative for I and positive for II.
◦ ΔS is positive for I and positive for II.

Question 2

According to the third law of thermodynamics,
◦ the entropy of the universe increases for any spontaneous process.
◦ the entropy of a perfectly ordered, crystalline substance is zero at 0 Kelvin.
◦ the entropy increases for any spontaneous process.
◦ energy is conserved in any transformation of matter.
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by rosent76 on Feb 15, 2020

chevyboi1976

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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rosent76

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Reply 2 on: Feb 15, 2020
Excellent

adammoses97

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Reply 3 on: Yesterday
Wow, this really help

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