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Author Question: What is the relationship between G, Qp, and Kp for a reaction involving gases? (Read 64 times)

LaDunn

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on: Feb 15, 2020

Question 1

If Q increases,
◦ ΔG decreases and the reaction becomes more spontaneous.
◦ ΔG increases and the reaction becomes more spontaneous.
◦ ΔG increases and the reaction becomes less spontaneous.
◦ ΔG decreases and the reaction becomes less spontaneous.

Question 2

What is the relationship between ΔG, Qp, and Kp for a reaction involving gases?
◦ ΔG = RTln(Kp/Qp)
◦ ΔG = Kp/Qp
◦ ΔG = RTln(Qp/Kp)
◦ ΔG = Qp/Kp
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by LaDunn on Feb 15, 2020

meow1234

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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LaDunn

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Reply 2 on: Feb 15, 2020
Great answer, keep it coming :)

flexer1n1

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Reply 3 on: Yesterday
Wow, this really help

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