Consider the following cell:
Pt(s) ∣ H2(g, p1) ∣ H+(aq, pHA) ∣∣ H+(aq, pHC) ∣ H2(g, p2) ∣ Pt(s)
Where pH
A is the pH of the aqueous solution in the anode half-cell and pH
C is the pH of the aqueous solution in the cathode half-cell. If the partial pressure of H
2(
g) is the same for both half-cells, (p
1 = p
2), then E for the cell at 25°C is
◦ 0.0296 V log (pH
A/pH
C).
◦ 0.0592 V (pH
C - pH
A).
◦ 0.0592 V (pH
A - pH
C).
◦ 0.0296 V log (pH
C/pH
A).