Question 1
O2(g) + 4 H+(aq) + 4 e- → 2 H2O(l) | E° = +1.23 V |
Pb2+(aq) + 2 e- → Pb(s) | E° = -0.13 V |
2 H2O(l) + 2 e- → H2(g) + 2 OH-(aq) | E° = -0.83 V |
Based on the half-reactions above, electrolysis of an aqueous solution of Pb(NO
3)
2 is expected to produce.
◦ O
2 at the cathode and Pb at the anode.
◦ Pb at the cathode and O
2 at the anode.
◦ H
2 at the cathode and Pb at the anode.
◦ Pb at the cathode and H
2 at the anode.
Question 2
The chlor-alkali industry is based on the electrolysis of aqueous NaCl. What are the products of this electrolysis?
◦ NaOH, H
2, and Cl
2◦ NaOH, O
2, and Cl
2◦ Na and Cl
2◦ NaOH, H
2, and O
2