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WhattoUnderstand

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Question 1

For a galvanic cell that uses the following two half-reactions,

Cr2O72-(aq) + 14 H+(aq) + 6 e- → 2 Cr3+(aq) + 7 H2O(l)
Pb(s) → Pb2+(aq) + 2 e-

how many moles of Pb(s) are oxidized by one mole of Cr2O72-?
◦ 6
◦ 3
◦ 1
◦ 2

Question 2

What is the reduction half-reaction for the following overall cell reaction?

Pb2+(aq) + 2 Ag(s) → Pb(s) + 2 Ag+(aq)


◦ Ag+(aq) + e- → Ag(s)
◦ Pb2+(aq) + 2 e- → Pb(s)
◦ Ag(s) + e- → Ag+(aq)
◦ Pb2+(aq) + e- → Pb(s)


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Marked as best answer by WhattoUnderstand on Feb 15, 2020

macmac

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WhattoUnderstand

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Reply 2 on: Feb 15, 2020
Gracias!


abro1885

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Reply 3 on: Yesterday
Wow, this really help

 

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