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Author Question: Analyze the following code:if (x < 100) && (x > 10) System.out.println("x is between 10 and 100"); (Read 270 times)

kwoodring

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on: May 6, 2020

Question 1

Suppose x=10 and y=10. What is x after evaluating the expression (y >= 10) || (x++ > 10)?
◦ 9
◦ 10
◦ 11

Question 2

Analyze the following code:

if (x < 100) && (x > 10)
System.out.println("x is between 10 and 100");

◦ The statement has compile errors because (x<100) & (x > 10) must be enclosed inside parentheses.
◦ The statement has compile errors because (x<100) & (x > 10) must be enclosed inside parentheses and the println(…) statement must be put inside a block.
◦ The statement compiles fine, but has a runtime error.
◦ The statement compiles fine.
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Marked as best answer by kwoodring on May 6, 2020

ambernicolefink

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Reply #1 on: May 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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kwoodring

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Reply 2 on: May 6, 2020
Gracias!

meganmoser117

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Reply 3 on: Yesterday
Wow, this really help

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