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Author Question: What is y displayed in the following code?public class Test1 { public static void main(String[] ... (Read 83 times)

folubunmi

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What is y displayed in the following code?

public class Test1 {
public static void main(String[] args) {
int x = 1;
int y = x = x + 1;
System.out.println("y is " + y);
}
}

◦ y is 0.
◦ y is 2 because x + 1 is assigned to x and then x is assigned to y.
◦ The program has a compile error since x is redeclared in the statement int y = x = x + 1.
◦ y is 1 because x is assigned to y first.


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Marked as best answer by folubunmi on May 6, 2020

Loise Hard

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folubunmi

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Reply 2 on: May 6, 2020
Wow, this really help


Joy Chen

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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