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Author Question: The area under a graph of ax vs. t from t = ti to t = tf represents (Read 50 times)

NClaborn

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on: Aug 1, 2020

Question 1

In 20 minutes, Kara ran 2.40 km on a treadmill facing due east. Relative to the gym, what were her displacement and average velocity during this time interval?

◦
0; 0

◦
0; 2.00 m/s

◦
2.40 km, east; 0

◦
2.40 km, east; 2.00 m/s, east

◦
2.40 km, west; 2.00 m/s, west


Question 2

The area under a graph of ax vs. t from t = ti to t = tf represents

◦
xf−xi.

◦
vf−vi.

◦
xavg.

◦
vavg.

◦
aavg.
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by NClaborn on Aug 1, 2020

ryrychapman11

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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NClaborn

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Reply 2 on: Aug 1, 2020
Great answer, keep it coming :)

kswal303

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Reply 3 on: Yesterday
Gracias!

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