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Author Question: The equation that solves a problem is . The problem is: (Read 136 times)

tth

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on: Aug 1, 2020

Question 1

The area under a graph of vx vs. t from t = ti to t = tf represents

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xi.

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xf.

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xf−xi.

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(xi + xf).

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xi + xf.


Question 2

The equation that solves a problem is . The problem is:

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What is the initial velocity of a car that goes from rest to 18 m/s in 3.0 s?

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What is the final velocity of a car that goes from rest to 18 m/s in 3.0 s?

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What is the initial velocity of a car that accelerates at 18 m/s for 3.0 s?

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What is the final velocity of a car that accelerates at 3.0 m/s2 over a 6.0 m distance?

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What is the final velocity of a car that accelerates at 3.0 m/s2 over a 3.0 m distance?
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Marked as best answer by tth on Aug 1, 2020

amcvicar

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tth

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  • Posts: 579
Reply 2 on: Aug 1, 2020
YES! Correct, THANKS for helping me on my review

phuda

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Reply 3 on: Yesterday
Gracias!

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