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Author Question: The position of a particle as it moves along the x axis is given for t> 0 by x = (t3 3t2 + 6t) m, ... (Read 102 times)

jasdeep_brar

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on: Aug 1, 2020

Question 1

The position of a particle as it moves along the x axis is given by x = 15e−2t m, where t is in s. What is the acceleration of the particle at t = 1.0 s?

◦
22 m/s

◦
60 m/s

◦
8.1 m/s

◦
15 m/s

◦
35 m/s


Question 2

The position of a particle as it moves along the x axis is given for t> 0 by x = (t3− 3t2 + 6t) m, where t is in s. Where is the particle when it achieves its minimum speed (after t = 0)?

◦
3 m

◦
4 m

◦
8 m

◦
2 m

◦
7 m
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by jasdeep_brar on Aug 1, 2020

janeli

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jasdeep_brar

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Reply 2 on: Aug 1, 2020
:D TYSM

bulacsom

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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