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Author Question: Aline and Charlie are arguing as to whether or not it is possible in principle for an elevator to ... (Read 91 times)

mpobi80

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on: Aug 1, 2020

Question 1

A person weighing 0.70 kN rides in an elevator that has an upward acceleration of 1.5 m/s2. What is the magnitude of the force of the elevator floor on the person?

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0.11 kN

◦
0.81 kN

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0.70 kN

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0.59 kN

◦
0.64 kN


Question 2

Aline and Charlie are arguing as to whether or not it is possible in principle for an elevator to have an acceleration of magnitude greater than g. In the course of their discussion they come up with the statements below. Which one is correct?

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No, because once reaches g, the elevator is in free fall.

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No, because an acceleration greater than g is not possible.

◦
Yes, because it can reach an acceleration greater than g when the cable breaks.

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Yes, because it can reach an acceleration greater than g if the motor is strong enough.

◦
No, because it cannot exceed its terminal acceleration.
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by mpobi80 on Aug 1, 2020

jessicaduplan

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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mpobi80

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Reply 2 on: Aug 1, 2020
Great answer, keep it coming :)

ultraflyy23

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Reply 3 on: Yesterday
Wow, this really help

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