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Author Question: When a crate of mass m is dragged a distance d along a surface with coefficient of kinetic friction ... (Read 336 times)

jparksx

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on: Aug 1, 2020

Question 1

When a crate of mass m is dragged a distance d along a surface with coefficient of kinetic friction μk, then dragged back along the same path to its original position, the work done by friction is

◦
0.

◦
−μkmgd.

◦
+μkmgd.

◦
−2μkmgd.

◦
+2μkmgd.


Question 2

When a crate of mass m is dragged a distance d along a surface with coefficient of kinetic friction μk, then dragged back along the same path to its original position, the work done by friction is

◦
0.

◦
−μkmgd.

◦
+μkmgd.

◦
−2μkmgd.

◦
+2μkmgd.
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by jparksx on Aug 1, 2020

vkodali

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jparksx

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Reply 2 on: Aug 1, 2020
YES! Correct, THANKS for helping me on my review

ghepp

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Reply 3 on: Yesterday
:D TYSM

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