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Author Question: The equation below describes a physical situation: Which description best fits the equation? (Read 198 times)

Chelseaamend

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on: Aug 1, 2020
The equation below describes a physical situation:

    
    


Which description best fits the equation?

◦
A 1.70 kg block slows down while sliding down a frictionless plane inclined at a 30° angle.

◦
A 1.70 kg block slows down while sliding down a plane with μk = 0.320, with the plane inclined at a 30° angle.

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A 1.70 kg block speeds up while sliding up a frictionless plane inclined at a 30° angle.

◦
A 1.70 kg block speeds up while sliding down a plane with μk = 0.320, with the plane inclined at a 30° angle.

◦
A 1.70 kg block slides over the top of an inclined plane and then descends on the other side. Both planes, inclined at a 30° angle, have μk = 0.320.
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by Chelseaamend on Aug 1, 2020

hugthug12

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Chelseaamend

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Reply 2 on: Aug 1, 2020
Wow, this really help

pratush dev

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Reply 3 on: Yesterday
Excellent

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