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Author Question: Melanie says that when a diver enters an underwater cave of height h, the pressure on her is no ... (Read 45 times)

maegan_martin

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on: Aug 6, 2020
Melanie says that when a diver enters an underwater cave of height h, the pressure on her is no greater than ρWgh. Rosalind says that if the bottom of the cave is a distance H below the water surface, the pressure on the soles of the diver's feet can reach ρWgH. Which one, if either, is correct? (The density of water is ρW.)

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Melanie, because the roof of the cave absorbs the water pressure from above.

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Melanie, because only the fluid directly above any volume of the fluid can contribute to the pressure on that volume.

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Rosalind, because a fluid exerts equal pressure in all directions at a given depth.

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Rosalind, because the pressure also depends on the density, ρc, of the material above the cave roof, so that p = ρcg(H−h) + ρWgh.

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Melanie, because the pressure equals p = ρWgH−ρcg(H−h).
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by maegan_martin on Aug 6, 2020

cswans24

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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maegan_martin

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Reply 2 on: Aug 6, 2020
Thanks for the timely response, appreciate it

jomama

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Reply 3 on: Yesterday
:D TYSM

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