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Author Question: The wavelength of light visible to the human eye is on the order of 5 107 m. If the speed of light ... (Read 123 times)

vinney12

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on: Aug 6, 2020

Question 1

The wave equation is written down in an exam as

    


From dimensional considerations we see that

◦
v2 should be replaced by .

◦
v2 should be replaced by .

◦
v2 should be replaced by v.

◦
v2 should be replaced by .

◦
v2 should be replaced by .


Question 2

The wavelength of light visible to the human eye is on the order of 5 × 10−7 m. If the speed of light in air is 3 × 108 m/s, find the frequency of the lightwave.

◦
3 × 107 Hz

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4 × 109 Hz

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5 × 1011 Hz

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6 × 1014 Hz

◦
4 × 1015 Hz
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by vinney12 on Aug 6, 2020

ghepp

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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vinney12

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Reply 2 on: Aug 6, 2020
Wow, this really help

tandmlomax84

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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