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Author Question: A student has written the equation below to convert a temperature in degrees Fahrenheit into ... (Read 57 times)

corkyiscool3328

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on: Aug 6, 2020
A student has written the equation below to convert a temperature in degrees Fahrenheit into Kelvins. What is wrong with this equation?

    

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The factor in front of TF should be .

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The numerical factor should multiply (TF− 32).

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An additional 273.15 Kelvins must be added to the right side of the equation.

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All the corrections above are required.

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Only corrections (b) and (c) are required.
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by corkyiscool3328 on Aug 6, 2020

carojassy25

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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corkyiscool3328

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Reply 2 on: Aug 6, 2020
Wow, this really help

triiciiaa

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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