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Author Question: A 0.16 pF parallel-plate capacitor is charged to 10 V. Then the battery is disconnected from the ... (Read 376 times)

tiara099

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on: Aug 6, 2020

Question 1

A 0.16 pF parallel-plate capacitor is charged to 10 V. Then the battery is disconnected from the capacitor. When 1.00 × 107 electrons are now placed on the negative plate of the capacitor, the voltage between the plates changes by

◦
−5.0 V.

◦
−1.1 V.

◦
0 V.

◦
+1.1 V.

◦
+5.0 V.


Question 2

A 0.16 pF parallel-plate capacitor is charged to 10 V. Then the battery is disconnected from the capacitor. When 1.00 × 107 positive charges of magnitude |e| are now placed on the positive plate of the capacitor, the voltage between the plates changes by

◦
−5.0 V.

◦
−1.1 V.

◦
0 V.

◦
+1.1 V.

◦
+5.0 V.
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by tiara099 on Aug 6, 2020

katieost

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Jackie Chen

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Reply #2 on: Jun 15, 2021
Thank you


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