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Author Question: Given that s is a String, what does the following loop do? (Read 115 times)

BrownTown3

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on: Aug 30, 2020

Question 1

The following code has a syntax error immediately before the word else.  What is the error and why does it arise?  Fix the code so that this statement is a legal if-else statement.


Question 2

Given that s is a String, what does the following loop do?

◦ it prints s out backwards
◦ it prints s out forwards
◦ it prints s out backwards after skipping the last character
◦ it prints s out backwards but does not print the 0th character
◦ it yields a run-time error because there is no character at s.charAt(j-1) for j = 0
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Marked as best answer by BrownTown3 on Aug 30, 2020

Eazy416

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Reply #1 on: Aug 30, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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BrownTown3

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Reply 2 on: Aug 30, 2020
Wow, this really help

carlsona147

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Reply 3 on: Yesterday
:D TYSM

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