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Author Question: You want addEm to now add all three values and return the sum and changeEm to change x and y, but ... (Read 58 times)

cagreen833

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on: Aug 30, 2020



You want addEm to now add all three values and return the sum and changeEm to change x and y, but leave z alone.  Which should you do?
◦ Redefine addEm and changeEm without referencing super.addEm( ) or super.changeEm( )
◦ Redefine addEm to return the value of z + super.addEm( ), but leave changeEm alone
◦ Redefine changeEm to call super.changeEm( ) and then set z = x + y, but leave addEm alone
◦ Redefine addEm to return the value of z + super.addEm( ) and redefine changeEm to call super.changeEm( ) and then set z = x + y
◦ Redefine changeEm to call super.changeEm( ) without doing anything to z, and redefine addEm to return super.addEm( )
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Marked as best answer by cagreen833 on Aug 30, 2020

mcni194

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Reply #1 on: Aug 30, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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cagreen833

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Reply 2 on: Aug 30, 2020
Wow, this really help

jordangronback

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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