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Author Question: The following method recognizes whether a String parameter consists of a specific pattern and ... (Read 439 times)

oliviahorn72

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on: Aug 30, 2020
The following method recognizes whether a String parameter consists of a specific pattern and returns true if the String has that pattern, false otherwise.  Use this recursive method to answer the questions below.




If the statement a.substring(1, a.length( ) - 1) were changed to be (a.substring(1, a.length( )), then the method would
◦ have infinite recursion unless the String were null
◦ always return true
◦ always return false
◦ return true only if all characters of the String were the same
◦ return true only the String had only two characters and they were the same
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Marked as best answer by oliviahorn72 on Aug 30, 2020

robbielu01

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Reply #1 on: Aug 30, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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oliviahorn72

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Reply 2 on: Aug 30, 2020
Great answer, keep it coming :)

Dominic

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Reply 3 on: Yesterday
Gracias!

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