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Author Question: A steel can in the shape of a right circular cylinder must be designed to hold 650 ... (Read 3158 times)

rayancarla1

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on: Feb 28, 2021
Solve the problem.

A steel can in the shape of a right circular cylinder must be designed to hold 650 cubic centimeters of juice (see figure). It can be shown that the total surface area of the can (including the ends) is given by S(r) = 2πr2 + , where r is the radius of the can in centimeters. Using the TABLE feature of a graphing utility, find the radius that minimizes the surface area (and thus the cost) of the can. Round to the nearest tenth of a centimeter.

◦ 4.7 cm
◦ 0 cm
◦ 5.9 cm
◦ 3.9 cm
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by rayancarla1 on Feb 28, 2021

sailorcrescent

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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RadnomUesr45646

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Reply #2 on: Oct 4, 2022
Thank you


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