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Author Question: The amount of water (in gallons) in a leaky bathtub is given in the table below. ... (Read 4251 times)

dbose

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on: Feb 28, 2021
Solve the problem.

The amount of water (in gallons) in a leaky bathtub is given in the table below. Using a graphing utility, fit the data to a third degree polynomial (or a cubic). Then approximate the time at which there is maximum amount  of water in the tub, and estimate the time when the water runs out of the tub. Express all your answers rounded to two decimal places.



◦ maximum amount of water after 8.23 minutes; water runs out after 19.73 minutes
◦ maximum amount of water after 5.37 minutes; water runs out after 11.06 minutes
◦ maximum amount of water after 5.31 minutes; water runs out after 8.23 minutes
◦ maximum amount of water after 5.31 minutes; water never runs out
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by dbose on Feb 28, 2021

31809pancho

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Akash Singh

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Reply #2 on: Apr 16, 2021
Thank you


jdude1023

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Reply #3 on: Apr 30, 2021
thank you


Cameron Price

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Reply #4 on: May 2, 2022
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Colin Gonzalez

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Reply #5 on: May 25, 2022
awesome


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