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Author Question: A cup of coffee is heated to 194 and is then allowed to cool in a room whose air ... (Read 93 times)

humphriesbr@me.com

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on: Feb 28, 2021
Solve the problem.

A cup of coffee is heated to 194° and is then allowed to cool in a room whose air temperature is After 11 minutes, the temperature of the cup of coffee is Find the time needed for the coffee to cool to a temperature of 102°. Assume the cooling follows Newton's Law of Cooling:
 U = T + (Uo - T)ekt.
(Round your answer to one decimal place.)
◦ 41.1 minutes
◦ 26.4 minutes
◦ 15.1 minutes
◦ 29.7 minutes
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by humphriesbr@me.com on Feb 28, 2021

macagn

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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humphriesbr@me.com

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Reply 2 on: Feb 28, 2021
Excellent

ASDFGJLO

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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