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Author Question: The temperature (in degrees Fahrenheit) of a dead body that has been cooling in a ... (Read 72 times)

anjilletteb

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on: Feb 28, 2021
Solve the problem.

The temperature (in degrees Fahrenheit) of a dead body that has been cooling in a room set at 70° is measured as 88°.  One hour later, the body temperature is 87.5°. How long (to the nearest hour) before the first measurement was the time of death, assuming that the body temperature of the deceased at the time of death was 98.6°. Assume the cooling follows Newton's Law of Cooling:
 U = T + (Uo - T)ekt.
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by anjilletteb on Feb 28, 2021

frre432

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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anjilletteb

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Reply 2 on: Feb 28, 2021
Thanks for the timely response, appreciate it

robbielu01

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Reply 3 on: Yesterday
Wow, this really help

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