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Author Question: A mass hangs from a spring which oscillates up and down. The position P (in feet) ... (Read 97 times)

jake

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on: Feb 28, 2021
Solve the problem.

A mass hangs from a spring which oscillates up and down. The position P (in feet) of the mass at time t (in seconds) is given by P = 4 cos (4t). For what values of t, 0 ≤ t < π, will the position be 2 feet? Find the exact values. Do not use a calculator.
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by jake on Feb 28, 2021

mcabuhat

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jake

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Reply 2 on: Feb 28, 2021
Gracias!

kusterl

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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