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Author Question: An object is propelled upward at an angle , 45 < < 90, to the horizontal with an ... (Read 57 times)

LCritchfi

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on: Feb 28, 2021
Solve the problem.

An object is propelled upward at an angle θ, 45° < θ < 90°, to the horizontal with an initial velocity of v0 feet per second from the base of a plane that makes an angle of 45° with the horizontal. If air resistance is ignored, the distance R that it travels up the inclined plane is given by the function
R(θ) = [sin(2θ) - cos(2θ) - 1].
Show that
R(θ) = [sin θ(cos θ + sin θ) - 1].
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by LCritchfi on Feb 28, 2021

otokexnaru

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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LCritchfi

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Reply 2 on: Feb 28, 2021
Wow, this really help

kswal303

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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