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Author Question: A baseball player hit a baseball with an initial speed of 190 feet per second at ... (Read 126 times)

jparksx

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Solve the problem.

A baseball player hit a baseball with an initial speed of 190 feet per second at an angle of 40° to the horizontal. The ball was hit at a height of 4 feet off the ground. Find parametric equations that describe the motion of the ball as a function of time. How long is the ball in the air? When is the ball at its maximum height? What is the distance the ball traveled?
◦ x = 145.54t, y = -16t2 + 122.17t + 4
7.668 sec, 3.818 sec,
1116.001 feet
◦ x = 145.54t, y = -16t2 + 122.17t + 4
7.603 sec, 3.818 sec,
1106.541 feet
◦ x = 145.54t, y = -16t2 + 122.17t + 4
7.668 sec, 3.818 sec,
1877.571 feet
◦ x = 145.54t, y = -16t2 + 122.17t + 4
15.336 sec, 3.818 sec,
2232.001 feet


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Marked as best answer by jparksx on Feb 28, 2021

ryhom

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jparksx

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Reply 2 on: Feb 28, 2021
Thanks for the timely response, appreciate it


ASDFGJLO

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Reply 3 on: Yesterday
Excellent

 

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