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Author Question: Rachel's bus leaves at 2:40 PM and accelerates at the rate of 4 meters per second ... (Read 48 times)

mmm

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on: Feb 28, 2021
Solve the problem.

Rachel's bus leaves at 2:40 PM and accelerates at the rate of 4 meters per second per second. Rachel, who can run 4 meters per second, arrives at the bus station 4 seconds after the bus has left. Find parametric equations that describe the motions of the bus and Rachel as a function of time. Determine algebraically whether Rachel will catch the bus. If so, when?
◦ Bus: x1 = 2t2, y1 = 1;  Rachel: x2 = 4(t - 4), y2 = 3
Rachel won't catch the bus.
◦ Bus: x1 = 4t2, y1 = 1;  Rachel: x2 = 2(t - 4), y2 = 3
Rachel will catch the bus at 2:44 PM
◦ Bus: x1 = 2t2, y1 = 1;  Rachel: x2 = 4(t + 4), y2 = 3
Rachel won't catch the bus.
◦ Bus: x1 = 2t2, y1 = 1;  Rachel: x2 = 4(t - 4), y2 = 3
Rachel will catch the bus at 2:45 PM
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by mmm on Feb 28, 2021

bobsmith

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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mmm

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Reply 2 on: Feb 28, 2021
Gracias!

abro1885

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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