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Author Question: The diagonal of the floor of a rectangular office cubicle is 2 ft longer than the ... (Read 62 times)

audie

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on: Feb 28, 2021
Solve the problem.

The diagonal of the floor of a rectangular office cubicle is 2 ft longer than the length of the cubicle and 5 ft longer than twice the width. Find the dimensions of the cubicle. Round to the nearest tenth, if necessary.
◦ width = 2 ft, length = 9 ft
◦ width = 3.9 ft, length = 9.7 ft
◦ width = 4 ft, length = 11 ft
◦ width = 9.7 ft, length = 22.4 ft
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by audie on Feb 28, 2021

tanna.moeller

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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audie

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Reply 2 on: Feb 28, 2021
YES! Correct, THANKS for helping me on my review

brbarasa

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Reply 3 on: Yesterday
Wow, this really help

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