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Author Question: The focal length f of a lens with index of refraction n is = (n - 1) where R1and ... (Read 197 times)

CharlieWard

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on: Feb 28, 2021
Solve the problem.

The focal length f of a lens with index of refraction n is = (n - 1) where R1and R2 are the radii of curvature of the front and back surfaces of the lens. Express f as a rational expression.
◦ f =
◦ f =
◦ f =
◦ f =
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by CharlieWard on Feb 28, 2021

kiamars2010

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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CharlieWard

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Reply 2 on: Feb 28, 2021
Gracias!

Jossy

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Reply 3 on: Yesterday
Excellent

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