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Author Question: Consider the following reaction: What mass of CCl4 will be formed if 1.20 moles of methane react ... (Read 204 times)

ashley

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on: Mar 21, 2021

Question 1

Consider the following reaction:

   

What mass of CCl4 is formed by the reaction of 4.80 g of methane with an excess of chlorine?


◦ 11.5 g
◦ 0.50 g
◦ 738 g
◦ 46.0 g
◦ none of these are correct

Question 2

Consider the following reaction:
   
What mass of CCl4 will be formed if 1.20 moles of methane react with 1.06 moles of chlorine?

◦ 185 g
◦ 163 g
◦ 652 g
◦ 40.8 g
◦ 18.8 g
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Marked as best answer by ashley on Mar 21, 2021

strudel15

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ashley

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Reply 2 on: Mar 21, 2021
Gracias!

skipfourms123

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Reply 3 on: Yesterday
Wow, this really help

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