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Author Question: A crystal was analyzed with x-rays having 2.58 wavelength. The angle of first-order diffraction (n ... (Read 75 times)

Melani1276

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on: Mar 21, 2021

Question 1

A crystal was analyzed with x-rays having 1.50 Å wavelength. A reflection was produced at θ = 24.3°. Assuming n = 1, what is the distance between the layers of atoms in the crystal?

◦ 7.29 Å
◦ 3.65 Å
◦ 0.549 Å
◦ 0.823 Å
◦ 1.82 Å

Question 2

A crystal was analyzed with x-rays having 2.58 Å wavelength. The angle of first-order diffraction (n = 1) was 19.8°. What would be the angle for second-order diffraction (n = 2)?

◦ 39.6 Å
◦ 42.6 Å
◦ 9.75 Å
◦ 15.2 Å
◦ 4.86 Å
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by Melani1276 on Mar 21, 2021

joshbk44

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Melani1276

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Reply 2 on: Mar 21, 2021
Wow, this really help

anyusername12131

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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