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Author Question: When one mole of benzene is vaporized at a constant pressure of 1.00 atm and at its boiling point of ... (Read 55 times)

kamilo84

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on: Mar 21, 2021
When one mole of benzene is vaporized at a constant pressure of 1.00 atm and at its boiling point of 353.0 K, 30.40 kJ of energy (heat) is absorbed and the volume change is +28.90 L. What is ΔE for this process? (1 L·atm = 101.3 J)

◦ 30.40 kJ
◦ 59.30 kJ
◦ 33.33 kJ
◦ 1.50 kJ
◦ 27.47 kJ
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Marked as best answer by kamilo84 on Mar 21, 2021

vseab

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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kamilo84

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Reply 2 on: Mar 21, 2021
YES! Correct, THANKS for helping me on my review

billybob123

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Reply 3 on: Yesterday
:D TYSM

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