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Author Question: A solution of two liquids, A and B, shows negative deviation from Raoult's law. This means that: (Read 34 times)

erika

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on: Mar 21, 2021
A solution of two liquids, A and B, shows negative deviation from Raoult's law. This means that:

◦ the molecules of A interact strongly with other A-type molecules.
◦ the two liquids have a positive heat of solution.
◦ molecules of A interact weakly, if at all, with B molecules.
◦ the molecules of A hinder the strong interaction between B molecules.
◦ molecules of A interact more strongly with B than A with A, or B with B.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by erika on Mar 21, 2021

rekilledagain

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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erika

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Reply 2 on: Mar 21, 2021
Wow, this really help

helenmarkerine

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Reply 3 on: Yesterday
Gracias!

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