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Author Question: You have a 10.40-g mixture of table sugar (C12H22O11) and table salt (NaCl). When this mixture is ... (Read 92 times)

809779

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on: Mar 21, 2021
You have a 10.40-g mixture of table sugar (C12H22O11) and table salt (NaCl). When this mixture is dissolved in 150. g of water, the freezing point is found to be –2.24°C. Calculate the percent by mass of sugar in the original mixture.

◦ 39.0%
◦ 43.8%
◦ 53.9%
◦ 61.0%
◦ none of these are correct
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Marked as best answer by 809779 on Mar 21, 2021

krakiolit

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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809779

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Reply 2 on: Mar 21, 2021
Wow, this really help

tkempin

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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