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Author Question: Consider the following reaction: 2HF(g) H2(g) + F2(g) (K = 1.00 102)Given 1.00 mole of HF(g), ... (Read 32 times)

ericka1

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on: Mar 21, 2021

Question 1

Consider the following reaction: CS2(g) + 4H2(g) CH4(g) + 2H2S(g). The equilibrium constant K is about 0.28 at 900°C. What is Kp at this temperature?

◦ 2.6 × 103
◦ 2.0 × 10–5
◦ 3.0 × 10–5
◦ 2.7 × 101
◦ 1.1 × 10–3

Question 2

Consider the following reaction:

    2HF(g) H2(g) + F2(g)     (K = 1.00 10–2)

Given 1.00 mole of HF(g), 0.276 mole of H2(g), and 0.750 mole of F2(g) are mixed in a 5.00-L flask, determine the reaction quotient, Q.


◦ Q = 0.0414
◦ Q = 0.207
◦ Q = 0.0518
◦ Q = 2.03
◦ None of these are correct.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by ericka1 on Mar 21, 2021

miss_1456@hotmail.com

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ericka1

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Reply 2 on: Mar 21, 2021
Wow, this really help

kswal303

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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