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Author Question: When 2.4 102 mol of nicotinic acid (a monoprotic acid) is dissolved in 350 mL of water, the pH is ... (Read 89 times)

daltonest1984

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on: Mar 21, 2021

Question 1

What is the pOH of pure water at 20oC? (Kw at 20oC = 6.87 × 10–15)

◦ 6.918
◦ 7.000
◦ 14.000
◦ 14.163
◦ 7.082

Question 2

When 2.4 × 10–2 mol of nicotinic acid (a monoprotic acid) is dissolved in 350 mL of water, the pH is 3.05. Calculate the Ka of nicotinic acid.

◦ 1.3 × 10–2
◦ 1.2 × 10–5
◦ 6.8 × 10–2
◦ 3.4 × 10–5
◦ None of these are correct.
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Marked as best answer by daltonest1984 on Mar 21, 2021

bfulkerson77

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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daltonest1984

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Reply 2 on: Mar 21, 2021
Great answer, keep it coming :)

essyface1

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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