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Author Question: 15.0 mL of 0.50 M NaOH is added to a 100.-mL sample of 0.379 M NH3 (Kb for NH3 = 1.8 105). What is ... (Read 116 times)

dejastew

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on: Mar 21, 2021

Question 1

15.0 mL of 0.50 M HCl is added to a 100.-mL sample of 0.478 M HNO2 (Ka for HNO2 = 4.0 × 10–4). What is the equilibrium concentration of NO2– ions?

◦ 2.5 × 10–3M
◦ 1.7 × 10–4M
◦ 4.2 × 10–1M
◦ 5.0 × 10–2M
◦ None of these are correct.

Question 2

15.0 mL of 0.50 M NaOH is added to a 100.-mL sample of 0.379 M NH3 (Kb for NH3 = 1.8 × 10–5). What is the equilibrium concentration of NH4+ ions?

◦ 9.5 × 10–3M
◦ 5.9 × 10–6M
◦ 3.3 × 10–1M
◦ 9.1 × 10–5M
◦ None of these are correct.
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Marked as best answer by dejastew on Mar 21, 2021

Carliemb17

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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dejastew

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Reply 2 on: Mar 21, 2021
Thanks for the timely response, appreciate it

Chelseyj.hasty

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Reply 3 on: Yesterday
:D TYSM

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