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Author Question: A 50.00-mL solution of 0.0680 M trimethylamine (Kb = 6.5 105) is titrated with a 0.0153 M solution ... (Read 82 times)

aabwk4

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on: Mar 21, 2021

Question 1

A 50.00-mL solution of 0.0423 M acetic acid (Ka = 1.8 × 10–5) is titrated with a 0.0249 M solution of sodium hydroxide as the titrant. What is the pH of at the equivalence point? (Kw = 1.00 × 10–14)

◦ 8.47
◦ 5.53
◦ 4.74
◦ 10.73
◦ 9.26

Question 2

A 50.00-mL solution of 0.0680 M trimethylamine (Kb = 6.5 × 10–5) is titrated with a 0.0153 M solution of hydrochloric acid as the titrant. What is the pH of the base solution after 20.82 mL of titrant have been added? (Kw = 1.00 × 10–14)

◦ 11.32
◦ 12.83
◦ 4.19
◦ 10.74
◦ 3.26
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Marked as best answer by aabwk4 on Mar 21, 2021

lou

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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aabwk4

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Reply 2 on: Mar 21, 2021
Wow, this really help

FergA

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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