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Author Question: A solution contains 10. mmol of H3PO4 and 5.0 mmol of NaH2PO4. How many milliliters of 0.10 M NaOH ... (Read 142 times)

haleyc112

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on: Mar 21, 2021

Question 1

A solution contains 0.500 M HA (Ka = 1.0 10–8) and 0.398 M NaA. What is the [H+] after 0.10 mole of HCl is added to 1.00 L of this solution?

◦ 1.0 × 10–8M
◦ 3.4 × 10–8M
◦ 5.0 × 1021M
◦ 2.0 × 10–8M
◦ None of these are correct.

Question 2

A solution contains 10. mmol of H3PO4 and 5.0 mmol of NaH2PO4. How many milliliters of 0.10 M NaOH must be added to reach the second equivalence point of the titration of the H3PO4 with NaOH?

◦ 250
◦ 150
◦ 1.0 × 102

◦ 50
◦ 2.0 × 102
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Marked as best answer by haleyc112 on Mar 21, 2021

trampas

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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haleyc112

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Reply 2 on: Mar 21, 2021
Wow, this really help

parshano

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Reply 3 on: Yesterday
Excellent

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