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Author Question: If 25.0 mL of 0.451 M NaOH solution is titrated with 0.253 M H2SO4, the flask at the endpoint will ... (Read 45 times)

jake

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on: Mar 21, 2021

Question 1

If 25 mL of 0.750 M HCl are added to 100. mL of 0.339 M NaOH, what is the final pH?

◦ 13.08
◦ 0.92
◦ 13.43
◦ 0.57
◦ 7.00

Question 2

If 25.0 mL of 0.451 M NaOH solution is titrated with 0.253 M H2SO4, the flask at the endpoint will contain (besides the indicator phenolphthalein) as the principal components:

◦ sodium hydroxide, sulfuric acid, and water
◦ dissolved sodium sulfate and water
◦ sodium hydroxide, sodium sulfate, and water
◦ dissolved sodium sulfate, sulfuric acid, and water
◦ precipitated sodium sulfate and water
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by jake on Mar 21, 2021

ricroger

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jake

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Reply 2 on: Mar 21, 2021
YES! Correct, THANKS for helping me on my review

carlsona147

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Reply 3 on: Yesterday
:D TYSM

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