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Author Question: Given the following values of equilibrium constants: Cu(OH)2(s) Cu2+(aq) + 2OH(aq) Ksp = 1.63 ... (Read 68 times)

jenna1

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on: Mar 21, 2021
Given the following values of equilibrium constants:
    Cu(OH)2(s) Cu2+(aq) + 2OH–(aq)     Ksp = 1.63 × 10–19
    Cu(NH3)42+(aq) Cu2+(aq) + 4NH3(aq)     K = 1.0 × 10–13
What is the value of the equilibrium constant for the following reaction?
    Cu(OH)2(s) + 4NH3(aq) Cu(NH3)42+(aq) + 2OH–(aq)

◦ 1.63 × 10–19

◦ 1.6 × 10–32

◦ 1.6 × 10–6

◦ 6.13 × 1018

◦ 1.0 × 1013
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by jenna1 on Mar 21, 2021

mochi09

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jenna1

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Reply 2 on: Mar 21, 2021
:D TYSM

apple

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Reply 3 on: Yesterday
Gracias!

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