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Author Question: For a certain process at 355 K, G = 11.8 kJ and H = 9.2 kJ. Therefore, S for the process is (Read 23 times)

fox

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on: Mar 21, 2021

Question 1

Elemental sulfur exists in two crystalline forms, rhombic and monoclinic. From the following data, calculate the equilibrium temperature at which monoclinic sulfur and rhombic sulfur are in equilibrium.    
 
ΔHf° (kJ/mol)
S° (J/K·mol)
S (rhombic)
0
31.880
S (monoclinic)
0.30
32.553
 

​


◦ 446 K
◦ 202 K
◦ –202 K
◦ –446 K
◦ 0 K

Question 2

For a certain process at 355 K, ΔG = –11.8 kJ and ΔH = –9.2 kJ. Therefore, ΔS for the process is

◦ 0 J/K·mol
◦ 7.3 J/K·mol
◦ –7.3 J/K·mol
◦ –25.9 J/K·mol
◦ 25.9 J/K·mol
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by fox on Mar 21, 2021

paavo

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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fox

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Reply 2 on: Mar 21, 2021
:D TYSM

coreycathey

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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