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Author Question: For the process S8 (rhombic) S8 (monoclinic) at 110C, H = 3.21 kJ/mol and S = 8.70 J/K mol (at ... (Read 17 times)

RRMR

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on: Mar 21, 2021
For the process S8 (rhombic) → S8 (monoclinic) at 110°C, ΔH = 3.21 kJ/mol and ΔS = 8.70 J/K ⋅ mol (at 110°C).

Which of the following is correct?


◦ This reaction is spontaneous at 110°C (S8 (monoclinic) is stable).
◦ This reaction is spontaneous at 110°C (S8 (rhombic) is stable).
◦ This reaction is nonspontaneous at 110°C (S8 (rhombic) is stable).
◦ This reaction is nonspontaneous at 110°C (S8 (monoclinic) is stable).
◦ Additional information is needed.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by RRMR on Mar 21, 2021

jointhecircus

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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RRMR

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Reply 2 on: Mar 21, 2021
YES! Correct, THANKS for helping me on my review

sultana.d

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Reply 3 on: Yesterday
Excellent

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